PyMongo backend

Pretty simple PyMongo backend.

Flask-Admin does not make assumptions about document structure, so you will have to configure ModelView to do what you need it to do.

This is bare minimum you have to provide for Flask-Admin view to work with PyMongo:

1. Provide list of columns by setting column_list property
2. Provide form to use by setting form property
3. When instantiating flask.ext.admin.contrib.pymongo.ModelView class, you have to provide PyMongo collection object

This is minimal PyMongo view:

class UserForm(Form):
    name = TextField('Name')
    email = TextField('Email')

class UserView(ModelView):
    column_list = ('name', 'email')
    form = UserForm

if __name__ == '__main__':
    admin = Admin(app)

    # 'db' is PyMongo database object
    admin.add_view(UserView(db['users']))

On top of that you can add sortable columns, filters, text search, etc.

For more documentation, check flask.ext.admin.contrib.pymongo documentation.

PyMongo integration example is here.